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Full Version: How to start the installation oF Windows Vista/7/XP with grub4dos when
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I would like to start the installation of Vista/7/Xp using their unpacked installation files saved inside a folder. Let's say that I want to start a new installation of Windows 7 and the old installation of Windows 7 is on (hd0,0) / (hd0,1). This is the situation :

Disk /dev/hd0 : 320 GB

/dev/(hd0,0) = the first hidden partition created by Vista/7,it is the boot partition.
/dev/(hd0,1) = the Windows Vista/7 files are saved here,it's the main partition.

I saved the Windows Vista/7 installation files on (hd0,1)/7/ and I'm using this menu.lst configuration file (saved on the root of the CD/ROM with grub.exe,because I boot the computer first with FreeDOS) :

title Start the installation of Windows Vista/7
root (hd0,1)
chainloader (hd0,1)/7/bootmgr

grub4dos should chainload the bootmgr located inside the folder specified on the menu.lst file,but it doesn't. This is the error message given :

File: \Boot\BCD

Status : 0xc000000f

An error occurred while attempting to read the boot configuration data. Any suggestion ?
QUOTE (marietto @ Aug 25 2010, 12:22 AM) *
Any suggestion ?

Yes smile.gif
No need to post here once you posted on the grub4dos forum:

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